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Mechanical Metallurgy Syllabus

April 02, 2025

GATE MT - Mechanical Metallurgy

Mechanical Metallurgy

Complete Guide for GATE Metallurgy (MT) - Section 6 (TestUrSelf)

6.1 Stress and Strain Analysis

Stress and Strain Tensors

Stress Tensor (σij)

σxx
τxy
τxz
τyx
σyy
τyz
τzx
τzy
σzz

Strain Tensor (εij)

εxx
γxy/2
γxz/2
γyx/2
εyy
γyz/2
γzx/2
γzy/2
εzz

Mohr's Circle Representation

Mohr's Circle Diagram

Mohr's Circle for 2D stress state

Center: C = (σx + σy)/2
Radius: R = √[((σx - σy)/2)² + τxy²]
Principal Stresses: σ1,2 = C ± R

Elasticity, Stiffness and Compliance Tensors

Generalized Hooke's Law

σij = Cijklεkl

Where Cijkl is the stiffness tensor (4th rank, 81 components)

For Isotropic Materials

C1111 = C2222 = C3333 = λ + 2μ
C1122 = C1133 = C2233 = λ
C1212 = C1313 = C2323 = μ

Where λ and μ are Lamé constants:

λ = Eν/[(1+ν)(1-2ν)]
μ = G = E/[2(1+ν)]

Yield Criteria

Von Mises Criterion

1 - σ2)² + (σ2 - σ3)² + (σ3 - σ1)² = 2σy²

Tresca Criterion

max(|σ1 - σ2|, |σ2 - σ3|, |σ3 - σ1|) = σy
Yield Criteria Comparison

Comparison of Von Mises and Tresca yield criteria

6.2 Plastic Deformation

Slip and Twinning

Slip Systems

Crystal Structure Slip Plane Slip Direction # Slip Systems
FCC {111} <110> 12
BCC {110}, {112}, {123} <111> 48
HCP (0001) <11-20> 3

Schmid's Law

τCRSS = σcosφcosλ

Where φ is angle between stress axis and slip plane normal, λ is angle between stress axis and slip direction

Twinning

K1 = {10-12} ⟨10-1-1⟩ for HCP metals

Twinning shear (γ) for common metals:

γ = s/2 where s is twinning shear magnitude

6.3 Dislocation Theory

Dislocation Types

Edge Dislocation

Edge Dislocation

Edge dislocation with extra half-plane

b ⊥ dislocation line

Screw Dislocation

Screw Dislocation

Screw dislocation with spiral ramp

b ∥ dislocation line

Mixed Dislocation

b = bedge + bscrew

Dislocation Dynamics

Stress Fields

Edge dislocation:

σxx = -[Gb/(2π(1-ν))][y(3x²+y²)/(x²+y²)²]
σyy = [Gb/(2π(1-ν))][y(x²-y²)/(x²+y²)²]

Screw dislocation:

σxz = -[Gb/(2π)][y/(x²+y²)]
σyz = [Gb/(2π)][x/(x²+y²)]

Dislocation Energy

E = [Gb²/(4πK)]ln(R/r0)

Where K = 1 for screw, K = 1-ν for edge dislocations

Frank-Read Source

Critical stress: τc = Gb/L

Where L is segment length between pinning points

6.4 Strengthening Mechanisms

Work/Strain Hardening

σ = σ0 + Kεn

Where n is strain hardening exponent (0.1-0.5 for metals)

Grain Boundary Strengthening (Hall-Petch)

σy = σ0 + kyd-1/2

Solid Solution Strengthening

Δτ = Gb√(cε)

Where c is solute concentration, ε is size misfit parameter

Precipitation Strengthening

Δτ = Gb/L (Orowan bypassing)
Δτ = γAPBb/r (Ordered precipitates)

6.5 Fracture Behavior

Griffith Theory

σf = √(2Eγs/πa)

Where γs is surface energy, a is crack length

Modified for Plasticity

σf = √(E(2γs + γp)/πa)

Where γp is plastic work per unit area

Linear Elastic Fracture Mechanics

Stress Intensity Factor

KI = Yσ√(πa)

Where Y is geometry factor (~1 for center crack)

Fracture Toughness

KIc = √(EGc)

Where Gc is critical strain energy release rate

Ductile-to-Brittle Transition

Tc = T0 + (1/β)ln(K̇/K̇0)

Where β is material constant, K̇ is loading rate

6.6 Fatigue

S-N Curve

σa = σ'f(2Nf)b

Where σ'f is fatigue strength coefficient, b is exponent

Crack Growth (Paris Law)

da/dN = C(ΔK)m

Where C and m are material constants

Endurance Limit

σe ≈ 0.5σu (for steels)

6.7 High Temperature Deformation

Creep Stages

ε = ε0 + βt1/3 + kt (Primary + Secondary)

Norton's Law

ε̇ = Aσnexp(-Q/RT)

Where n is stress exponent, Q is activation energy

Larson-Miller Parameter

P = T(C + log tr)

Where C ≈ 20 for many metals

TestUrSelf's Course Features

Mechanical Metallurgy Mastery Course

Course Highlights

  • 600+ practice problems with detailed solutions
  • Interactive dislocation dynamics simulations
  • 12 full-length mock tests with performance analysis
  • Microstructure interpretation workshops
  • Fracture surface analysis exercises

Special Modules

Module Topics Problems
1 Stress-Strain Analysis 120
2 Dislocation Theory 150
3 Fracture Mechanics 130
4 Fatigue & Creep 100
5 Numerical Problem Solving 100